LC 74. Search a 2D Matrix

Alen Alex · February 10, 2024

LeetCode Link: 74. Search a 2D Matrix
Language: C#

Problem Statement

You are given an m x n integer matrix matrix with the following two properties:

Each row is sorted in non-decreasing order. The first integer of each row is greater than the last integer of the previous row. Given an integer target, return true if target is in matrix or false otherwise.

You must write a solution in O(log(m * n)) time complexity.

Examples

Example 1: img1 Input: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3
Output: true

Example 2:

img1

Input: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13 Output: false

Constraints

  • m == matrix.length
  • n == matrix[i].length
  • 1 <= m, n <= 100
  • -104 <= matrix[i][j], target <= 104

Solution

public class Solution 
{
    public bool SearchMatrix(int[][] matrix, int target) 
    {
        int i=0;

        if (matrix.Length == 0 || matrix[0].Length == 0 || matrix[0][0] > target)
        {
            return false;
        }

        while (i < matrix.Length && matrix[i][0] < target && matrix[i][matrix[i].Length - 1] < target)
        {
            i++;
        }

        return (i == matrix.Length)
                ? false
                : BinarySearch(matrix[i], target);
    }

    private bool BinarySearch(int[] nums, int target)
    {
        int l = 0, h = nums.Length;

        while (l <= h)
        {
            var m = (l + h)/2;

            if (nums[m] == target)
            {
                return true;
            }

            if (target > nums[m])
            {
                l = m + 1;
            }
            else
            {
                h = m - 1;
            }
        }

        return false;
    }
}

Complexity

Time Complexity: O(MlogN)
Space Complexity: O(1)

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